Find the Inverse
$$x^2+4x+3$$
Solve 2 Step Equation
$$2z-1=15$$
Linear Equation with Fractions
$$\frac{x}{4} – 5=\frac {1}{2}$$
Solve Quadratic Equation
$$(3x-2)^2 = 121$$
Quadratic: Standard to Vertex Form
$$x^2+16x+71=0$$
$$x^2+4x+3$$
$$2z-1=15$$
$$\frac{x}{4} – 5=\frac {1}{2}$$
$$(3x-2)^2 = 121$$
$$x^2+16x+71=0$$